Matematika Sekolah Menengah Pertama Q.

90² + 20²

Lim x³ + 2x - 60x
x → 8

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Q.

90² + 20²

Lim x³ + 2x - 60x
x → 8

--

nt : Mau ikutan Quiz nih ..
Boleh req yaww mau spam.

90² + 20²

= (90×90) + (20×20)

= 8.100 + 400

= 8.500

-

Lim x³ + 2x - 60x

x → 8

-

》x³ + 2x - 60x

》8³ + 2(8) - 60(8)

》(8×8×8) + 16 - 480

》(64×8) + 16 - 480

》512 + 16 - 480

》528 - 480

48

CMIIW![tex] \\ [/tex]

Penyelesaian soal :

[tex] \tt {90}^{2} + {20}^{2} [/tex]

[tex] \tt = (90 \times 90) + {20}^{2} [/tex]

[tex] \tt = 8.100 + {20}^{2} [/tex]

[tex] \tt = 8.100 + (20 \times 20)[/tex]

[tex] \tt = 8.100 + 400[/tex]

[tex] \tt = 8.500[/tex]

[tex] \\ [/tex]

[tex] \sf Lim \: x → 8 \: \: x {}^{3} + 2x - 60x[/tex]

[tex] \sf = 8 {}^{3} + 2(8) - 60(8)[/tex]

[tex] \sf = 8 {}^{3} +( 2 \times 8) -( 60 \times 8)[/tex]

[tex] \sf = 8 {}^{3} +16 -480[/tex]

[tex] \sf = 512 +16 -480[/tex]

[tex] \sf = 528 -480[/tex]

[tex] \sf =48[/tex]

[tex] \\ [/tex]

Tysm!

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